Optimal. Leaf size=84 \[ \frac{i (c+d x)}{2 f (a+i a \tan (e+f x))}+\frac{(c+d x)^2}{4 a d}+\frac{d}{4 f^2 (a+i a \tan (e+f x))}-\frac{i d x}{4 a f} \]
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Rubi [A] time = 0.0539644, antiderivative size = 84, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.143, Rules used = {3723, 3479, 8} \[ \frac{i (c+d x)}{2 f (a+i a \tan (e+f x))}+\frac{(c+d x)^2}{4 a d}+\frac{d}{4 f^2 (a+i a \tan (e+f x))}-\frac{i d x}{4 a f} \]
Antiderivative was successfully verified.
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Rule 3723
Rule 3479
Rule 8
Rubi steps
\begin{align*} \int \frac{c+d x}{a+i a \tan (e+f x)} \, dx &=\frac{(c+d x)^2}{4 a d}+\frac{i (c+d x)}{2 f (a+i a \tan (e+f x))}-\frac{(i d) \int \frac{1}{a+i a \tan (e+f x)} \, dx}{2 f}\\ &=\frac{(c+d x)^2}{4 a d}+\frac{d}{4 f^2 (a+i a \tan (e+f x))}+\frac{i (c+d x)}{2 f (a+i a \tan (e+f x))}-\frac{(i d) \int 1 \, dx}{4 a f}\\ &=-\frac{i d x}{4 a f}+\frac{(c+d x)^2}{4 a d}+\frac{d}{4 f^2 (a+i a \tan (e+f x))}+\frac{i (c+d x)}{2 f (a+i a \tan (e+f x))}\\ \end{align*}
Mathematica [A] time = 0.357973, size = 96, normalized size = 1.14 \[ \frac{\left (2 c f (2 f x-i)+d \left (2 f^2 x^2-2 i f x-1\right )\right ) \tan (e+f x)-i \left (2 c f (2 f x+i)+d \left (2 f^2 x^2+2 i f x+1\right )\right )}{8 a f^2 (\tan (e+f x)-i)} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.145, size = 139, normalized size = 1.7 \begin{align*}{\frac{1}{1+ \left ( \tan \left ( fx+e \right ) \right ) ^{2}} \left ({\frac{d{x}^{2}}{4\,a}}+{\frac{2\,icf+d}{4\,a{f}^{2}}}+{\frac{d{x}^{2} \left ( \tan \left ( fx+e \right ) \right ) ^{2}}{4\,a}}+{\frac{ \left ( -id+2\,cf \right ) \tan \left ( fx+e \right ) }{4\,a{f}^{2}}}+{\frac{ \left ( id+2\,cf \right ) x}{4\,af}}+{\frac{dx\tan \left ( fx+e \right ) }{2\,af}}+{\frac{ \left ( -id+2\,cf \right ) x \left ( \tan \left ( fx+e \right ) \right ) ^{2}}{4\,af}} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: RuntimeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.53055, size = 146, normalized size = 1.74 \begin{align*} \frac{{\left (2 i \, d f x + 2 i \, c f + 2 \,{\left (d f^{2} x^{2} + 2 \, c f^{2} x\right )} e^{\left (2 i \, f x + 2 i \, e\right )} + d\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{8 \, a f^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 0.405821, size = 128, normalized size = 1.52 \begin{align*} \begin{cases} \frac{\left (2 i a c f^{2} e^{2 i e} + 2 i a d f^{2} x e^{2 i e} + a d f e^{2 i e}\right ) e^{- 4 i e} e^{- 2 i f x}}{8 a^{2} f^{3}} & \text{for}\: 8 a^{2} f^{3} e^{4 i e} \neq 0 \\\frac{c x e^{- 2 i e}}{2 a} + \frac{d x^{2} e^{- 2 i e}}{4 a} & \text{otherwise} \end{cases} + \frac{c x}{2 a} + \frac{d x^{2}}{4 a} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.22761, size = 88, normalized size = 1.05 \begin{align*} \frac{{\left (2 \, d f^{2} x^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 4 \, c f^{2} x e^{\left (2 i \, f x + 2 i \, e\right )} + 2 i \, d f x + 2 i \, c f + d\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{8 \, a f^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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